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Re:

Posted: Wed May 20, 2020 3:17 am
by Azmodan
Marcus wrote: Fri Dec 19, 2008 11:47 am Rob,

I don't think anyone screwed up with the inner tens. The targets that have an inner ten ring (50 meter rifle and pistol and the 10 meter air pistol target) have an arbitrary dimension given for that inner ring. While the current rifle and air pistol targets were designed in 1988 with electronic scoring in mind, in the case of the 50 meter pistol target the dimensions predate electronic scoring by about 75 years.

With the exception of the air rifle target where a 10.2 is exactly an inner ten, all the others have the inner ten at some point between two adjacent "tenths scoring rings."

I did a few more calculations and found the distance that the center of the bullet or pellet needs to be from the center of the target for the "tenths" score and an approximate (or exact minimum distance for the inner ten.

10 meter air rifle
10.0----2.50 mm
10.1----2.25 mm
10.2----2.00 mm exact inner ten (by definition in the rules)
10.3----1.75 mm

10 meter air pistol (Spencer did this already above, but...)
10.3----5.60 mm
10.4----4.80 mm
inner ten----4.75 mm = 10.40625 rings
10.5----4.00 mm

50 meter rifle
10.3----5.60 mm
inner ten----5.30 mm = 10.3375 rings (Note:typo in my posting above)
10.4----4.80 mm

50 meter pistol (25 meter precision)
10.4----16.68 mm
inner ten----15.3 mm = 10.4496 rings (approx)
10.5----13.90 mm

25 meter pistol (rapid fire)
10.4----31.68 mm
inner ten----27.80 mm = 10.4735 rings (approx)
10.5----26.40 mm


So if you are using paper targets you still need to plug the questionable shot hole for the inner ten ring just as if it were any other scoring ring. This could make scoring paper targets longer (especially 25 meter where targets are scored on the frames). The ring is the inner ten, it just doesn't correspond to a fixed tenths score (except for air rifle).

Marcus
does anyone know the mathematical formula to determine the score from mm?
how, for air pistol for example, 4.75 mm = 10.40625?