How to measure the distance across an air rifle target?

guest. · Post by **guest.** » Mon Oct 26, 2009 12:25 am

Perhaps the title of my post is a little misleading. I'm curious to know how we measure 10.9 vs 10.4 in relation to Millimeters from dead center?

Let's say an air rilfe is holding a 10.4 group size. I presume that would mean a distance of X from the center out to 10.4 multiplied by two which would result in your diameter (or group size). Can someone assist me with finding the X value or how it is derived?

Thank you,

Peter

Spencer · Post by **Spencer** » Mon Oct 26, 2009 12:52 am

to calculate the decimal value of an ISSF Air Rifle shot for x mm and y mm coordinates of the center of the shot
raw value=11-(((sqrt (x.squared +y.squared))/2.5)
This is rounded down to the first decimal place

Bob-Riegl · Post by **Bob-Riegl** » Mon Oct 26, 2009 8:14 am

I think what your are referring to are the scores reported in tenths for finals. Which can be measured by using a proper Nonius Gauge (overlay). There are several gauges in a set which used to be available from USAS which cover the disciplines shot in International competitions. We use these gauges to Judge the scores for a finals in AP & FP. If I remember correctly they also include RF (+skid gauges), running deer---etc. "Doc"

Guest · Post by **Guest** » Mon Oct 26, 2009 10:06 am

Thanks for the great replies. I appeciate it.

To simplify the question further, how can i find the outer distance of two shots in millimeters? One shot was fired and given 10.4 and was perfectly placed on the y axis. Shot number two was fired and given 10.4 and was perfectly placed on the y axis too, however on the opposite side of the x axis (a 10.4 to the left and a 10.4 to the right). What's the outer distance in mm between the two shots

I think Spencer provided this to me, but I just wanted to make sure I asked this more clearly.

Peter

Spencer · Post by **Spencer** » Mon Oct 26, 2009 4:20 pm

Anonymous wrote:Thanks for the great replies. I appeciate it.

To simplify the question further, how can i find the outer distance of two shots in millimeters? One shot was fired and given 10.4 and was perfectly placed on the y axis. Shot number two was fired and given 10.4 and was perfectly placed on the y axis too, however on the opposite side of the x axis (a 10.4 to the left and a 10.4 to the right). What's the outer distance in mm between the two shots

I think Spencer provided this to me, but I just wanted to make sure I asked this more clearly.

Peter

(2 x 1.5) +4.5 = 7.5mm for the outside of a 10.4 group
1.5mm to 0,0 for the greatest distance for a 10.4